196v^2+28v+1=0

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Solution for 196v^2+28v+1=0 equation: 



196v^2+28v+1=0

a = 196; b = 28; c = +1;
Δ = b2-4ac
Δ = 282-4·196·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-28}{392}=-1/14$

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